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Oracle Introduction to Oracle9i: SQL Sample Questions:
1. Examine this statement:
SELECT student_id, gpa FROM student_grades WHERE gpa > &&value;
You run the statement once, and when prompted you enter a value of 2.0. A report is produced. What happens when you run the statement a second time?
A) You are asked whether you want a new value or if you want to run the report based on the previous value.
B) You are prompted to enter a new value.
C) A report is produced that matches the first report produced.
D) An error is returned.
2. Which three statements about subqueries are true? (Choose three)
A) A multiple row subquery can be compared by using the ">" operator.
B) A single row subquery can use the IN operator.
C) A multiple row subquery can retrieve multiple rows and multiple columns.
D) A single row subquery can retrieve only one column and one row.
E) A multiple row subquery can use the "=" operator.
F) A single row subquery can retrieve only one row but many columns.
3. Examine the data from the ORDERS and CUSTOMERS tables.
Evaluate the SQL statement:
SELECT * FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'Smith');
What is the result when the query is executed?
A) Option D
B) Option A
C) Option C
D) Option B
E) Option E
4. Which SELECT statement should you use to extract the year from the system date and display it in the format "1998"?
A) SELECT TO_CHAR(SUBSTR(SYSDATE, 8,2),'yyyy') FROM dual;
B) SELECT TO_DATE(SYSDATE,'yyyy') FROM dual;
C) SELECT DECODE(SUBSTR(SYSDATE, 8), 'YYYY') FROM dual;
D) SELECT DECODE(SUBSTR(SYSDATE, 8), 'year') FROM dual;
E) SELECT TO_CHAR(SYSDATE,'yyyy') FROM dual;
5. Examine the data in the EMPLOYEES and EMP_HIST tables:
The EMP_HIST table is updated at the end of every year. The employee ID, name, job ID, and salary of each existing employee are modified with the latest data. New employee details are added to the table.
Which statement accomplishes this task?
A) MERGE INTO emp_hist eh USING employees e WHEN MATCHED THEN UPDATE emp_hist SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT INTO emp_hist VALUES (e.employee_id, e.name, e.job_id, e.salary);
B) UPDATE emp_hist SET employee_id, name, job_id, salary = (SELECT employee_id, name, job_id, salary FROM employees) WHERE employee_id IN (SELECT employee_id FROM employees);
C) MERGE INTO emp_hist eh USING employees e ON (eh.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE emp hist SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT INTO emp_hist VALUES (e.employee_id, e.name, e.job_id, e.salary);
D) job id, e.salary);
E) MERGE INTO emp_hist eh USING employees e ON (eh.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT VALUES (e.employee id, e.name,
Solutions:
| Question # 1 Answer: C | Question # 2 Answer: B,C,F | Question # 3 Answer: A | Question # 4 Answer: E | Question # 5 Answer: E |






